Problem 1000. -- A+B Problem

POJ_1000: A+B Problem

Time Limit: 1000 MS  Memory Limit: 10 MB   64bit IO Format: %I64d
Submitted: 144  Accepted: 89
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Calculate a+b

Input

Two integer a,b (0<=a,b<=10)

Output a+b

`1 2`

`3`

HINT

Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so.

Here is a sample solution to problem 1000 using C++/G++:

`#include <iostream>using namespace std;int main(){    int a,b;    cin >> a >> b;    cout << a+b << endl;    return 0;}`
It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error.

Here is a sample solution to problem 1000 using C/GCC:

`#include <stdio.h>int main(){    int a,b;    scanf("%d %d",&a, &b);    printf("%d\n",a+b);    return 0;}`
Here is a sample solution to problem 1000 using Pascal:

`program p1000(Input,Output);var  a,b:Integer;begin   Readln(a,b);   Writeln(a+b);end.`
Here is a sample solution to problem 1000 using Java:

Now java compiler is jdk 1.5, next is program for 1000

`import java.io.*;import java.util.*;public class Main{            public static void main(String args[]) throws Exception            {                    Scanner cin=new Scanner(System.in);                    int a=cin.nextInt(),b=cin.nextInt();                    System.out.println(a+b);            }}`
Old program for jdk 1.4

`import java.io.*;import java.util.*;public class Main{    public static void main (String args[]) throws Exception    {        BufferedReader stdin =             new BufferedReader(                new InputStreamReader(System.in));        String line = stdin.readLine();        StringTokenizer st = new StringTokenizer(line);        int a = Integer.parseInt(st.nextToken());        int b = Integer.parseInt(st.nextToken());        System.out.println(a+b);    }}`
Here is a sample solution to problem 1000 using Fortran:

`	PROGRAM P1000		IMPLICIT NONE		INTEGER :: A, B		READ(*,*) A, B		WRITE(*, "(I0)") A + B	END PROGRAM P1000`

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